The discrimination of solubility of Pell equation ax2-mqy2=±1(a，b∈Z+,a,b is not a perfect square positive integer) is a very meaningful question.In this paper,by applying related knowledge of Legendre sign and nature of congruence,it works out sever conclusions that Pell equaton such as ax2-mqy2=±1(m∈Z+,2▕a,q≡±1(mod4),p is a prime factor,a,m,q is not perfect square number) has not positive integer solution.These conclusion play an important role in studying restricted Pell equation x2-Dy2=±1(D is a non-square positive integer).